Integrand size = 21, antiderivative size = 112 \[ \int \csc ^3(c+d x) (a+a \sec (c+d x))^n \, dx=-\frac {a (2-n) (a+a \sec (c+d x))^{-1+n}}{4 d (1-n)}+\frac {a (a+a \sec (c+d x))^{-1+n}}{2 d (1-\sec (c+d x))}-\frac {(2+n) \operatorname {Hypergeometric2F1}\left (1,n,1+n,\frac {1}{2} (1+\sec (c+d x))\right ) (a+a \sec (c+d x))^n}{8 d n} \]
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Time = 0.12 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {3958, 91, 80, 70} \[ \int \csc ^3(c+d x) (a+a \sec (c+d x))^n \, dx=-\frac {(n+2) (a \sec (c+d x)+a)^n \operatorname {Hypergeometric2F1}\left (1,n,n+1,\frac {1}{2} (\sec (c+d x)+1)\right )}{8 d n}-\frac {a (2-n) (a \sec (c+d x)+a)^{n-1}}{4 d (1-n)}+\frac {a (a \sec (c+d x)+a)^{n-1}}{2 d (1-\sec (c+d x))} \]
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Rule 70
Rule 80
Rule 91
Rule 3958
Rubi steps \begin{align*} \text {integral}& = -\frac {a^4 \text {Subst}\left (\int \frac {x^2 (a-a x)^{-2+n}}{(-a-a x)^2} \, dx,x,-\sec (c+d x)\right )}{d} \\ & = \frac {a (a+a \sec (c+d x))^{-1+n}}{2 d (1-\sec (c+d x))}+\frac {\text {Subst}\left (\int \frac {(a-a x)^{-2+n} \left (-a^3 n+2 a^3 x\right )}{-a-a x} \, dx,x,-\sec (c+d x)\right )}{2 d} \\ & = -\frac {a (2-n) (a+a \sec (c+d x))^{-1+n}}{4 d (1-n)}+\frac {a (a+a \sec (c+d x))^{-1+n}}{2 d (1-\sec (c+d x))}-\frac {\left (a^2 (2+n)\right ) \text {Subst}\left (\int \frac {(a-a x)^{-1+n}}{-a-a x} \, dx,x,-\sec (c+d x)\right )}{4 d} \\ & = -\frac {a (2-n) (a+a \sec (c+d x))^{-1+n}}{4 d (1-n)}+\frac {a (a+a \sec (c+d x))^{-1+n}}{2 d (1-\sec (c+d x))}-\frac {(2+n) \operatorname {Hypergeometric2F1}\left (1,n,1+n,\frac {1}{2} (1+\sec (c+d x))\right ) (a+a \sec (c+d x))^n}{8 d n} \\ \end{align*}
Time = 1.07 (sec) , antiderivative size = 179, normalized size of antiderivative = 1.60 \[ \int \csc ^3(c+d x) (a+a \sec (c+d x))^n \, dx=\frac {\cos (c+d x) \sec ^2\left (\frac {1}{2} (c+d x)\right ) (1+\sec (c+d x))^{-n} (a (1+\sec (c+d x)))^n \left (2^{1+n} \operatorname {Hypergeometric2F1}\left (1,1-n,2-n,\cos (c+d x) \sec ^2\left (\frac {1}{2} (c+d x)\right )\right ) \left (\cos ^2\left (\frac {1}{2} (c+d x)\right ) \sec (c+d x)\right )^n+2^n \operatorname {Hypergeometric2F1}\left (2,1-n,2-n,\cos (c+d x) \sec ^2\left (\frac {1}{2} (c+d x)\right )\right ) \left (\cos ^2\left (\frac {1}{2} (c+d x)\right ) \sec (c+d x)\right )^n+(1+\sec (c+d x))^n\right )}{8 d (-1+n)} \]
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\[\int \csc \left (d x +c \right )^{3} \left (a +a \sec \left (d x +c \right )\right )^{n}d x\]
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\[ \int \csc ^3(c+d x) (a+a \sec (c+d x))^n \, dx=\int { {\left (a \sec \left (d x + c\right ) + a\right )}^{n} \csc \left (d x + c\right )^{3} \,d x } \]
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\[ \int \csc ^3(c+d x) (a+a \sec (c+d x))^n \, dx=\int \left (a \left (\sec {\left (c + d x \right )} + 1\right )\right )^{n} \csc ^{3}{\left (c + d x \right )}\, dx \]
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\[ \int \csc ^3(c+d x) (a+a \sec (c+d x))^n \, dx=\int { {\left (a \sec \left (d x + c\right ) + a\right )}^{n} \csc \left (d x + c\right )^{3} \,d x } \]
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\[ \int \csc ^3(c+d x) (a+a \sec (c+d x))^n \, dx=\int { {\left (a \sec \left (d x + c\right ) + a\right )}^{n} \csc \left (d x + c\right )^{3} \,d x } \]
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Timed out. \[ \int \csc ^3(c+d x) (a+a \sec (c+d x))^n \, dx=\int \frac {{\left (a+\frac {a}{\cos \left (c+d\,x\right )}\right )}^n}{{\sin \left (c+d\,x\right )}^3} \,d x \]
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